What are the solutions to the equation -x^2+3x=0 ?

The solutions to the equation -x^2+3x=0 are x=0,x=3

Find the zeros of -x^2+3x=0

The zeros of -x^2+3x=0 are x=0,x=3

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- x^{2} + 3 x = 0

x = 0, x = 3

Solution steps

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

9 z^{2} + 30 z + 25

12 x^{2} - 48 x + 36

4 (9 - w) - 20 = 20 - 2 w

6 x^{3} - 5 x^{2} y - 24 x y^{2} + 20 y^{3}

(x + 2) (x - 5) = 0

What are the solutions to the equation -x^2+3x=0 ?
The solutions to the equation -x^2+3x=0 are x=0,x=3
Find the zeros of -x^2+3x=0
The zeros of -x^2+3x=0 are x=0,x=3