What are the solutions to the equation -2t^2=-18 ?

The solutions to the equation -2t^2=-18 are t=3,t=-3

Find the zeros of -2t^2=-18

The zeros of -2t^2=-18 are t=3,t=-3

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- 2 t^{2} = - 18

t = 3, t = - 3

Solution steps

- 2 t^{2} = - 18

Divide both sides by

- 2

t^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 9, t = - 9

9 = 3

- 9 = - 3

t = 3, t = - 3

5 m^{2} + 12 m + 7

\frac{x + 2}{24} = \frac{9}{2}

15 < ∣ - 2 d - 3 ∣ + 6

4 (a + b)^{2} - (a - b)^{2}

4^{\frac{3}{5}} \times 4^{\frac{1}{5}}

What are the solutions to the equation -2t^2=-18 ?
The solutions to the equation -2t^2=-18 are t=3,t=-3
Find the zeros of -2t^2=-18
The zeros of -2t^2=-18 are t=3,t=-3