What is 2pi(128/5-64+64/3) ?

The solution to 2pi(128/5-64+64/3) is -(512pi)/(15)

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simplify 2pi(128/5-64+64/3)

simplify

2 π (\frac{128}{5} - 64 + \frac{64}{3})

- \frac{512 π}{15}

Decimal Notation

- 107.23302 \dots

Solution steps

2 π (\frac{128}{5} - 64 + \frac{64}{3})

Group like terms

= 2 π (\frac{64}{3} + \frac{128}{5} - 64)

Join

\frac{64}{3} + \frac{128}{5} - 64 : - \frac{256}{15}

= 2 π (- \frac{256}{15})

Remove parentheses:

(- a) = - a

= - 2 π \frac{256}{15}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{256 \cdot 2 π}{15}

Multiply the numbers:

256 \cdot 2 = 512

= - \frac{512 π}{15}

(\frac{2}{2})^{4}

(8 a^{6} b^{\frac{3}{2}})^{\frac{2}{3}}

(x - 2)^{2} + (x + 1)^{2} = 49

\frac{6 - 3 5}{2 + 5}

\frac{s ^{2} t ^{- 4}}{5 s ^{- 1} t}

What is 2pi(128/5-64+64/3) ?
The solution to 2pi(128/5-64+64/3) is -(512pi)/(15)