What is the answer to solvefor x,8xy=2(2x+y) ?

The answer to solvefor x,8xy=2(2x+y) is x= y/(2(2y-1));\quad y\ne 1/2

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solvefor x,8xy=2(2x+y)

solve for

x, 8 x y = 2 (2 x + y)

x = \frac{y}{2 ( 2 y - 1 )}; y \neq = \frac{1}{2}

Solution steps

8 x y = 2 (2 x + y)

Expand

2 (2 x + y) : 4 x + 2 y

8 x y = 4 x + 2 y

Move

4 x

to the left side

8 x y - 4 x = 2 y

Factor

8 x y - 4 x : 4 x (2 y - 1)

4 x (2 y - 1) = 2 y

Divide both sides by

4 (2 y - 1); y \neq = \frac{1}{2}

x = \frac{y}{2 ( 2 y - 1 )}; y \neq = \frac{1}{2}

x, 3 x - 2 y + 4 z = 11

0.01 x + 3.1 = 2.03 x - 2.96

2 t - 12 - 3 t = 60

3 x + 2 = 5 x - 10

1 - 3.8 a - 0.8 = - 4.7 a - 1.6

What is the answer to solvefor x,8xy=2(2x+y) ?
The answer to solvefor x,8xy=2(2x+y) is x= y/(2(2y-1));\quad y\ne 1/2