What is the answer to solvefor x,xyz=(10^n)(x+y) ?

The answer to solvefor x,xyz=(10^n)(x+y) is x=(10^ny}{yz-10^n};\quad y\ne \frac{10^n)/z

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solvefor x,xyz=(10^n)(x+y)

solve for

x, x yz = (1 0^{n}) (x + y)

x = \frac{1 0 ^{n} y}{yz - 1 0 ^{n}}; y \neq = \frac{1 0 ^{n}}{z}

Solution steps

x yz = (1 0^{n}) (x + y)

Expand

(1 0^{n}) (x + y) : 1 0^{n} x + 1 0^{n} y

x yz = 1 0^{n} x + 1 0^{n} y

Move

1 0^{n} x

to the left side

x yz - 1 0^{n} x = 1 0^{n} y

Factor

x yz - 1 0^{n} x : x (yz - 1 0^{n})

x (yz - 1 0^{n}) = 1 0^{n} y

Divide both sides by

yz - 1 0^{n}; y \neq = \frac{1 0 ^{n}}{z}

x = \frac{1 0 ^{n} y}{yz - 1 0 ^{n}}; y \neq = \frac{1 0 ^{n}}{z}

b, d = 5 f + \frac{1}{5} mb

4 (4 b + 8) = - 2 (- 7 - 11 b)

x, 3 x + 9 y = 6

9 = \frac{x}{7}

12 m - 5 = 11 m - 5

What is the answer to solvefor x,xyz=(10^n)(x+y) ?
The answer to solvefor x,xyz=(10^n)(x+y) is x=(10^ny}{yz-10^n};\quad y\ne \frac{10^n)/z