What are the solutions to the equation -8x^2+x+3=0 ?

The solutions to the equation -8x^2+x+3=0 are x=-(-1+sqrt(97))/(16),x=(1+sqrt(97))/(16)

Find the zeros of -8x^2+x+3=0

The zeros of -8x^2+x+3=0 are x=-(-1+sqrt(97))/(16),x=(1+sqrt(97))/(16)

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- 8 x^{2} + x + 3 = 0

x = - \frac{- 1 + 97}{16}, x = \frac{1 + 97}{16}

Solution steps

- 8 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 8 ) \cdot 3}{2 ( - 8 )}

1^{2} - 4 (- 8) \cdot 3 = 97

x_{1, 2} = \frac{- 1 \pm 97}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 1 + 97}{2 ( - 8 )}, x_{2} = \frac{- 1 - 97}{2 ( - 8 )}

x = \frac{- 1 + 97}{2 ( - 8 )} : - \frac{- 1 + 97}{16}

x = \frac{- 1 - 97}{2 ( - 8 )} : \frac{1 + 97}{16}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 97}{16}, x = \frac{1 + 97}{16}

16 x - 4

2 (- 3 x + 4) = 5 x + 2

- 1.6 (10 x + 6) = 9.1 x + 5.6 (4 x + 1)

8 (4 x + 6) = - (x - 7)

6 x^{4} + 7 x^{3} - 23 x^{2} - 14 x + 24

What are the solutions to the equation -8x^2+x+3=0 ?
The solutions to the equation -8x^2+x+3=0 are x=-(-1+sqrt(97))/(16),x=(1+sqrt(97))/(16)
Find the zeros of -8x^2+x+3=0
The zeros of -8x^2+x+3=0 are x=-(-1+sqrt(97))/(16),x=(1+sqrt(97))/(16)