What is the answer to solvefor x,y=f(x-4)+3 ?

The answer to solvefor x,y=f(x-4)+3 is x=(y-3)/f+4;\quad f\ne 0

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solvefor x,y=f(x-4)+3

solve for

x, y = f (x - 4) + 3

x = \frac{y - 3}{f} + 4; f \neq = 0

Solution steps

y = f (x - 4) + 3

Switch sides

f (x - 4) + 3 = y

Move

3

to the right side

f (x - 4) = y - 3

Divide both sides by

f; f \neq = 0

x - 4 = \frac{y - 3}{f}; f \neq = 0

Move

4

to the right side

x = \frac{y - 3}{f} + 4; f \neq = 0

d, ab = c d e

m, d = 2 m + 5 n

m, d = 2 m + 3 n

a x - 5 = b x + 2

- 14 = - 4 (9 x - 1)

What is the answer to solvefor x,y=f(x-4)+3 ?
The answer to solvefor x,y=f(x-4)+3 is x=(y-3)/f+4;\quad f\ne 0