What is the answer to solvefor x,2xy+5y^2=4 ?

The answer to solvefor x,2xy+5y^2=4 is x=(4-5y^2)/(2y);\quad y\ne 0

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solvefor x,2xy+5y^2=4

solve for

x, 2 x y + 5 y^{2} = 4

x = \frac{4 - 5 y ^{2}}{2 y}; y \neq = 0

Solution steps

2 x y + 5 y^{2} = 4

Move

5 y^{2}

to the right side

2 x y = 4 - 5 y^{2}

Divide both sides by

2 y; y \neq = 0

x = \frac{4 - 5 y ^{2}}{2 y}; y \neq = 0

20 - x = 3 (x - 4)

\frac{x}{\frac{1}{3}} = 2

3 x - 7 = 3 (x + 1)

15 = - 10 y

7 (n + 6) = 8 n + 39

What is the answer to solvefor x,2xy+5y^2=4 ?
The answer to solvefor x,2xy+5y^2=4 is x=(4-5y^2)/(2y);\quad y\ne 0