What are the solutions to the equation 8x^2+6x=-5 ?

The solutions to the equation 8x^2+6x=-5 are x=-3/8+i(sqrt(31))/8 ,x=-3/8-i(sqrt(31))/8

Find the zeros of 8x^2+6x=-5

The zeros of 8x^2+6x=-5 are x=-3/8+i(sqrt(31))/8 ,x=-3/8-i(sqrt(31))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 6 x = - 5

x = - \frac{3}{8} + i \frac{31}{8}, x = - \frac{3}{8} - i \frac{31}{8}

Solution steps

8 x^{2} + 6 x = - 5

Move

5

to the left side

8 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

Simplify

6^{2} - 4 \cdot 8 \cdot 5 : 231 i

x_{1, 2} = \frac{- 6 \pm 2 31 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 6 + 2 31 i}{2 \cdot 8}, x_{2} = \frac{- 6 - 2 31 i}{2 \cdot 8}

x = \frac{- 6 + 2 31 i}{2 \cdot 8} : - \frac{3}{8} + i \frac{31}{8}

x = \frac{- 6 - 2 31 i}{2 \cdot 8} : - \frac{3}{8} - i \frac{31}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} + i \frac{31}{8}, x = - \frac{3}{8} - i \frac{31}{8}

3 (22) - 30

12 - 3 (x + 5) = - 9

49 c^{2} - 16

mn - 4 m - 5 n + 20

\frac{34 x ^{10} y ^{9}}{2 x ^{8} y ^{6}}

What are the solutions to the equation 8x^2+6x=-5 ?
The solutions to the equation 8x^2+6x=-5 are x=-3/8+i(sqrt(31))/8 ,x=-3/8-i(sqrt(31))/8
Find the zeros of 8x^2+6x=-5
The zeros of 8x^2+6x=-5 are x=-3/8+i(sqrt(31))/8 ,x=-3/8-i(sqrt(31))/8