What is the answer to solvefor x,f(x+1)=(x+1)-2 ?

The answer to solvefor x,f(x+1)=(x+1)-2 is x=(-1-f)/(f-1);\quad f\ne 1

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solvefor x,f(x+1)=(x+1)-2

solve for

x, f (x + 1) = (x + 1) - 2

x = \frac{- 1 - f}{f - 1}; f \neq = 1

Solution steps

f (x + 1) = (x + 1) - 2

Remove parentheses:

(a) = a

f (x + 1) = x + 1 - 2

Add/Subtract the numbers:

1 - 2 = - 1

f (x + 1) = x - 1

Expand

f (x + 1) : x f + f

x f + f = x - 1

Move

f

to the right side

x f = x - 1 - f

Move

x

to the left side

x f - x = - 1 - f

Factor

x f - x : x (f - 1)

x (f - 1) = - 1 - f

Divide both sides by

f - 1; f \neq = 1

x = \frac{- 1 - f}{f - 1}; f \neq = 1

2 (n + 3) - 5 = 9

5 (2 x - 9) + 3 = - 7

y, 5 cy - d = 4 d - cy

75 = 3 (- 6 x - 5)

2 x - 3 (2 x + 2) = 1 - 5 (4 x + 3)

What is the answer to solvefor x,f(x+1)=(x+1)-2 ?
The answer to solvefor x,f(x+1)=(x+1)-2 is x=(-1-f)/(f-1);\quad f\ne 1