What are the solutions to the equation 3r^2-16r-7=5 ?

The solutions to the equation 3r^2-16r-7=5 are r=6,r=-2/3

Find the zeros of 3r^2-16r-7=5

The zeros of 3r^2-16r-7=5 are r=6,r=-2/3

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3 r^{2} - 16 r - 7 = 5

r = 6, r = - \frac{2}{3}

Decimal Notation

r = 6, r = - 0.66666 \dots

Solution steps

3 r^{2} - 16 r - 7 = 5

Move

5

to the left side

3 r^{2} - 16 r - 12 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 12) = 20

r_{1, 2} = \frac{- ( - 16 ) \pm 20}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- ( - 16 ) + 20}{2 \cdot 3}, r_{2} = \frac{- ( - 16 ) - 20}{2 \cdot 3}

r = \frac{- ( - 16 ) + 20}{2 \cdot 3} : 6

r = \frac{- ( - 16 ) - 20}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

r = 6, r = - \frac{2}{3}

\frac{1}{8} - \frac{2}{3}

7 x + 4 < 6 x - 1

x^{4} - 13 x^{2} - 48

x - 2 (x - 6) \leq 3 x

10 x - 35

What are the solutions to the equation 3r^2-16r-7=5 ?
The solutions to the equation 3r^2-16r-7=5 are r=6,r=-2/3
Find the zeros of 3r^2-16r-7=5
The zeros of 3r^2-16r-7=5 are r=6,r=-2/3