What is the answer to solvefor x,23x3y2+34x4-2=0 ?

The answer to solvefor x,23x3y2+34x4-2=0 is x= 1/(69y+68);\quad y\ne-68/69

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solvefor x,23x3y2+34x4-2=0

solve for

x, 23 x 3 y 2 + 34 x 4 - 2 = 0

x = \frac{1}{69 y + 68}; y \neq = - \frac{68}{69}

Solution steps

23 x \cdot 3 y \cdot 2 + 34 x \cdot 4 - 2 = 0

Multiply the numbers:

23 \cdot 3 \cdot 2 = 138

138 x y + 34 \cdot 4 x - 2 = 0

Multiply the numbers:

34 \cdot 4 = 136

138 x y + 136 x - 2 = 0

Move

2

to the right side

138 x y + 136 x = 2

Factor

138 x y + 136 x : 2 x (69 y + 68)

2 x (69 y + 68) = 2

Divide both sides by

2 (69 y + 68); y \neq = - \frac{68}{69}

x = \frac{1}{69 y + 68}; y \neq = - \frac{68}{69}

- 8 x = - 3 - (2.9 x + 5) + 1.3 x

f, D = \frac{1}{5} f k

x, - 2 x + 3 y = - 3

5 (2 - x) = 7 x - 26

5 (b - x) - 2 = 3 x - 3 b

What is the answer to solvefor x,23x3y2+34x4-2=0 ?
The answer to solvefor x,23x3y2+34x4-2=0 is x= 1/(69y+68);\quad y\ne-68/69