What are the solutions to the equation (a+1)(a+2)=0 ?

The solutions to the equation (a+1)(a+2)=0 are a=-1,a=-2

Find the zeros of (a+1)(a+2)=0

The zeros of (a+1)(a+2)=0 are a=-1,a=-2

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(a + 1) (a + 2) = 0

a = - 1, a = - 2

Solution steps

(a + 1) (a + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + 1 = 0 or a + 2 = 0

Solve

a + 1 = 0 : a = - 1

Solve

a + 2 = 0 : a = - 2

The solutions to the quadratic equation are:

a = - 1, a = - 2

\frac{1}{2} + \frac{1}{16}

∣ 5 x - 2 ∣ + 6 = 6

3 x + 178 = 6 x + 238

q (q + 5) = 0

x - 2 = 3 x^{2}

What are the solutions to the equation (a+1)(a+2)=0 ?
The solutions to the equation (a+1)(a+2)=0 are a=-1,a=-2
Find the zeros of (a+1)(a+2)=0
The zeros of (a+1)(a+2)=0 are a=-1,a=-2