What is the answer to 2x^2-15=2(x^2+7x) ?

The answer to 2x^2-15=2(x^2+7x) is x=-15/14

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2x^2-15=2(x^2+7x)

2 x^{2} - 15 = 2 (x^{2} + 7 x)

x = - \frac{15}{14}

Decimal Notation

x = - 1.07142 \dots

Solution steps

2 x^{2} - 15 = 2 (x^{2} + 7 x)

Expand

2 (x^{2} + 7 x) : 2 x^{2} + 14 x

2 x^{2} - 15 = 2 x^{2} + 14 x

Move

15

to the right side

2 x^{2} = 2 x^{2} + 14 x + 15

Subtract

2 x^{2} + 14 x

from both sides

2 x^{2} - (2 x^{2} + 14 x) = 2 x^{2} + 14 x + 15 - (2 x^{2} + 14 x)

Simplify

- 14 x = 15

Divide both sides by

- 14

x = - \frac{15}{14}

x, f = \frac{( x + 4 )}{2}

h + \frac{6}{5} = 2

- 4 x - 3 (- 8 x + 3.5) - 10 = 3.9

5 x - 18 = 8 + 3 x

m, n = \frac{4}{5} (m + 7)

What is the answer to 2x^2-15=2(x^2+7x) ?
The answer to 2x^2-15=2(x^2+7x) is x=-15/14
Solve for x: 2x^2-15=2(x^2+7x)
The solution is x=-15/14