What are the solutions to the equation -2x=x^2-1+2 ?

The solutions to the equation -2x=x^2-1+2 are x=-1

Find the zeros of -2x=x^2-1+2

The zeros of -2x=x^2-1+2 are x=-1

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- 2 x = x^{2} - 1 + 2

x = - 1

Solution steps

- 2 x = x^{2} - 1 + 2

Refine

- 2 x = x^{2} + 1

Switch sides

x^{2} + 1 = - 2 x

Move

2 x

to the left side

x^{2} + 1 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

81 x^{2} - 16 = 0

\frac{5 π}{3} + 4 π

∣ x + 2 ∣ \geq 1

6 p^{2} - 8 p + 6 = 0

- 3 (3 + 7 x) = 6 (x - 6) + 3 x

What are the solutions to the equation -2x=x^2-1+2 ?
The solutions to the equation -2x=x^2-1+2 are x=-1
Find the zeros of -2x=x^2-1+2
The zeros of -2x=x^2-1+2 are x=-1