What are the solutions to the equation -x^2+10x=x^2-6x ?

The solutions to the equation -x^2+10x=x^2-6x are x=0,x=8

Find the zeros of -x^2+10x=x^2-6x

The zeros of -x^2+10x=x^2-6x are x=0,x=8

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- x^{2} + 10 x = x^{2} - 6 x

x = 0, x = 8

Solution steps

- x^{2} + 10 x = x^{2} - 6 x

Move

6 x

to the left side

- x^{2} + 16 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 6^{2} - 4 (- 2) \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 ( - 2 )}, x_{2} = \frac{- 16 - 16}{2 ( - 2 )}

x = \frac{- 16 + 16}{2 ( - 2 )} : 0

x = \frac{- 16 - 16}{2 ( - 2 )} : 8

The solutions to the quadratic equation are:

x = 0, x = 8

\frac{3}{2} \cdot \frac{3}{2}

- 35 \leq 13 - 4 n \leq - 11

∣ 2 x - 9 ∣ - 7 > 0

(x - 6) (x + 8) > 0

x^{2} - 8 x + 41 = 0

What are the solutions to the equation -x^2+10x=x^2-6x ?
The solutions to the equation -x^2+10x=x^2-6x are x=0,x=8
Find the zeros of -x^2+10x=x^2-6x
The zeros of -x^2+10x=x^2-6x are x=0,x=8