What is the answer to (x-3)^2-8=(x+2)^2-23 ?

The answer to (x-3)^2-8=(x+2)^2-23 is x=2

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(x-3)^2-8=(x+2)^2-23

(x - 3)^{2} - 8 = (x + 2)^{2} - 23

x = 2

Solution steps

(x - 3)^{2} - 8 = (x + 2)^{2} - 23

Expand

(x - 3)^{2} - 8 : x^{2} - 6 x + 1

Expand

(x + 2)^{2} - 23 : x^{2} + 4 x - 19

x^{2} - 6 x + 1 = x^{2} + 4 x - 19

Move

1

to the right side

x^{2} - 6 x = x^{2} + 4 x - 20

Subtract

x^{2} + 4 x

from both sides

x^{2} - 6 x - (x^{2} + 4 x) = x^{2} + 4 x - 20 - (x^{2} + 4 x)

Simplify

- 10 x = - 20

Divide both sides by

- 10

x = 2

\frac{3 x}{2} - 7 = \frac{x}{4} - 2

2 (x - 5) - 4 x = 7 x + 9

5 - x = 10

\frac{2 x - 3}{2} = \frac{x - 5}{2}

1 - 3 y = - 1

What is the answer to (x-3)^2-8=(x+2)^2-23 ?
The answer to (x-3)^2-8=(x+2)^2-23 is x=2
Solve for x: (x-3)^2-8=(x+2)^2-23
The solution is x=2