What are the solutions to the equation 36^2+25y^2=900 ?

The solutions to the equation 36^2+25y^2=900 are y=(6sqrt(11))/5 i,y=-(6sqrt(11))/5 i

Find the zeros of 36^2+25y^2=900

The zeros of 36^2+25y^2=900 are y=(6sqrt(11))/5 i,y=-(6sqrt(11))/5 i

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3 6^{2} + 25 y^{2} = 900

y = \frac{6 11}{5} i, y = - \frac{6 11}{5} i

Solution steps

3 6^{2} + 25 y^{2} = 900

Move

3 6^{2}

to the right side

25 y^{2} = - 396

Divide both sides by

25

y^{2} = - \frac{396}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{396}{25}, y = - - \frac{396}{25}

- \frac{396}{25} = \frac{6 11}{5} i

- - \frac{396}{25} = - \frac{6 11}{5} i

y = \frac{6 11}{5} i, y = - \frac{6 11}{5} i

5 x^{2} + 11 x - 12

8 - (\frac{\frac{( 6 - x )}{2}}{3}) = 0

2 x + 11 \geq 17

\frac{2 x - 3}{x - 3} \leq 1

x^{4} - 121 y^{6}

What are the solutions to the equation 36^2+25y^2=900 ?
The solutions to the equation 36^2+25y^2=900 are y=(6sqrt(11))/5 i,y=-(6sqrt(11))/5 i
Find the zeros of 36^2+25y^2=900
The zeros of 36^2+25y^2=900 are y=(6sqrt(11))/5 i,y=-(6sqrt(11))/5 i