What is factor 5x^3-9x^2+48x+10 ?

The solution to factor 5x^3-9x^2+48x+10 is (5x+1)(x^2-2x+10)

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factor 5x^3-9x^2+48x+10

factor

5 x^{3} - 9 x^{2} + 48 x + 10

(5 x + 1) (x^{2} - 2 x + 10)

Solution steps

5 x^{3} - 9 x^{2} + 48 x + 10

Use the rational root theorem

a_{0} = 10, a_{n} = 5

The dividers of

a_{0} : 1, 2, 5, 10,

The dividers of

a_{n} : 1, 5

Therefore, check the following rational numbers:

\pm \frac{1 , 2 , 5 , 10}{1 , 5}

- \frac{1}{5}

is a root of the expression, so factor out

5 x + 1

= (5 x + 1) \frac{5 x ^{3} - 9 x ^{2} + 48 x + 10}{5 x + 1}

\frac{5 x ^{3} - 9 x ^{2} + 48 x + 10}{5 x + 1} = x^{2} - 2 x + 10

= (5 x + 1) (x^{2} - 2 x + 10)

2 a = 10

- 3 x^{2} + 4 x + 1 = 0

(1 + \frac{1}{100})^{100}

9 v^{2} - 1

3 x = 210

What is factor 5x^3-9x^2+48x+10 ?
The solution to factor 5x^3-9x^2+48x+10 is (5x+1)(x^2-2x+10)