What is the answer to x^2+2x+1=(x+1)^2 ?

The answer to x^2+2x+1=(x+1)^2 is True for all x

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x^2+2x+1=(x+1)^2

x^{2} + 2 x + 1 = (x + 1)^{2}

True for all x

Solution steps

x^{2} + 2 x + 1 = (x + 1)^{2}

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{2} + 2 x + 1 = x^{2} + 2 x + 1

Move

1

to the right side

x^{2} + 2 x = x^{2} + 2 x

Subtract

x^{2} + 2 x

from both sides

x^{2} + 2 x - (x^{2} + 2 x) = x^{2} + 2 x - (x^{2} + 2 x)

Simplify

0 = 0

Both sides are equal

True for all x

136 + 12 x = - 4 (1 - 2 x)

3 x - 2 x = 7

\frac{x - 7}{3} = - 12

N, q = N g

2 x + 9 = 19

What is the answer to x^2+2x+1=(x+1)^2 ?
The answer to x^2+2x+1=(x+1)^2 is True for all x
Solve for x: x^2+2x+1=(x+1)^2
The solution is True for all x