en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z=(i^{87})/((-2+3i))

Solution

z = \frac{i ^{87}}{( - 2 + 3 i )}

Solution

z = - \frac{3}{13} + i \frac{2}{13}

Solution steps

z = \frac{i ^{87}}{( - 2 + 3 i )}

Simplify

\frac{i ^{87}}{- 2 + 3 i} : - \frac{3}{13} + i \frac{2}{13}

z = - \frac{3}{13} + i \frac{2}{13}

Popular Examples

solvefor x,f(-3+x)=9-6x solve for

x, f (- 3 + x) = 9 - 6 x

solvefor x,-3x+3/2 y=12 solve for

x, - 3 x + \frac{3}{2} y = 12

9x-91+6x+76=180

9 x - 91 + 6 x + 76 = 180

\frac{- 5}{6} x = \frac{3}{4}

8(x-a)=2(2a-x),x

8 (x - a) = 2 (2 a - x), x

Frequently Asked Questions (FAQ)

What is the answer to z=(i^{87})/((-2+3i)) ?
The answer to z=(i^{87})/((-2+3i)) is z=-3/13+i 2/13