What is the answer to 7x+(5x+2)-[5x-2-(x+1)]=0 ?

The answer to 7x+(5x+2)-[5x-2-(x+1)]=0 is x=-5/8

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7x+(5x+2)-[5x-2-(x+1)]=0

7 x + (5 x + 2) - [5 x - 2 - (x + 1)] = 0

x = - \frac{5}{8}

Decimal Notation

x = - 0.625

Solution steps

7 x + (5 x + 2) - [5 x - 2 - (x + 1)] = 0

Remove parentheses:

(a) = a

7 x + 5 x + 2 - (5 x - 2 - (x + 1)) = 0

Add similar elements:

7 x + 5 x = 12 x

12 x + 2 - (5 x - 2 - (x + 1)) = 0

Move

2

to the right side

12 x - (5 x - 2 - (x + 1)) = - 2

Expand

12 x - (5 x - 2 - (x + 1)) : 8 x + 3

8 x + 3 = - 2

Move

3

to the right side

8 x = - 5

Divide both sides by

8

x = - \frac{5}{8}

- 10 + z - 1 = 7 z - 5

- 11 x = 22

6 + 5 (x + 1) = 26

5 + 3 x = 7 (x + 3)

x, 5 x - c = k

What is the answer to 7x+(5x+2)-[5x-2-(x+1)]=0 ?
The answer to 7x+(5x+2)-[5x-2-(x+1)]=0 is x=-5/8
Solve for x: 7x+(5x+2)-[5x-2-(x+1)]=0
The solution is x=-5/8