What is the answer to (3*5)t+(21-12)=15t+3^2 ?

The answer to (3*5)t+(21-12)=15t+3^2 is True for all t

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(3*5)t+(21-12)=15t+3^2

(3 \cdot 5) t + (21 - 12) = 15 t + 3^{2}

True for all t

Solution steps

(3 \cdot 5) t + (21 - 12) = 15 t + 3^{2}

Remove parentheses:

(a) = a

3 \cdot 5 t + 21 - 12 = 15 t + 3^{2}

Multiply the numbers:

3 \cdot 5 = 15

15 t + 21 - 12 = 15 t + 3^{2}

Add/Subtract the numbers:

21 - 12 = 9

15 t + 9 = 15 t + 3^{2}

3^{2} = 9

15 t + 9 = 15 t + 9

Move

9

to the right side

15 t = 15 t

Move

15 t

to the left side

0 = 0

Both sides are equal

True for all t

5 - 2 (3 x - 2) = 4 (3 x + 7)

3 x - 71 = 2 x - 50

3 (2 z + 4) = 6 (5 z + 2)

w, 6 w - w y = 2 y + 3

3 (x + 12) - 2 = 10

What is the answer to (3*5)t+(21-12)=15t+3^2 ?
The answer to (3*5)t+(21-12)=15t+3^2 is True for all t
Solve for t: (3*5)t+(21-12)=15t+3^2
The solution is True for all t