What is factor (5w^2z+15w-140)/(w^2+4w-21) ?

The solution to factor (5w^2z+15w-140)/(w^2+4w-21) is (5(w^2z+3w-28))/((w-3)(w+7))

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factor (5w^2z+15w-140)/(w^2+4w-21)

factor

\frac{5 w ^{2} z + 15 w - 140}{w ^{2} + 4 w - 21}

\frac{5 ( w ^{2} z + 3 w - 28 )}{( w - 3 ) ( w + 7 )}

Solution steps

\frac{5 w ^{2} z + 15 w - 140}{w ^{2} + 4 w - 21}

Factor

w^{2} + 4 w - 21 : (w - 3) (w + 7)

= \frac{5 w ^{2} z + 15 w - 140}{( w - 3 ) ( w + 7 )}

Factor

5 w^{2} z + 15 w - 140 : 5 (w^{2} z + 3 w - 28)

= \frac{5 ( w ^{2} z + 3 w - 28 )}{( w - 3 ) ( w + 7 )}

- 4 k^{2} + 2 k + 30

3 x^{4} - 11 x^{2} - 20

x^{2} + 6 x = - 10

10 x \leq - 3

What is factor (5w^2z+15w-140)/(w^2+4w-21) ?
The solution to factor (5w^2z+15w-140)/(w^2+4w-21) is (5(w^2z+3w-28))/((w-3)(w+7))