What is -3|x-6|>=-15 ?

The solution to -3|x-6|>=-15 is 1<= x<= 11

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-3|x-6|>=-15

- 3 ∣ x - 6 ∣ \geq - 15

1 \leq x \leq 11

Solution steps

- 3 ∣ x - 6 ∣ \geq - 15

Multiply both sides by

- 1

3 ∣ x - 6 ∣ \leq 15

Divide both sides by

3

∣ x - 6 ∣ \leq 5

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 5 \leq x - 6 \leq 5

x - 6 \geq - 5 and x - 6 \leq 5

x \geq 1 and x \leq 11

Merge Overlapping Intervals

1 \leq x \leq 11

2 x^{2} + 4 x - 9 = 2 (x - 1)

\frac{x - 10}{8} = 10

i^{- 2}

- \frac{13}{10} + \frac{1}{5}