What is the answer to (x-3)^2=(x-3)(x+2) ?

The answer to (x-3)^2=(x-3)(x+2) is x=3

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(x-3)^2=(x-3)(x+2)

(x - 3)^{2} = (x - 3) (x + 2)

x = 3

Solution steps

(x - 3)^{2} = (x - 3) (x + 2)

Expand

(x - 3)^{2} : x^{2} - 6 x + 9

Expand

(x - 3) (x + 2) : x^{2} - x - 6

x^{2} - 6 x + 9 = x^{2} - x - 6

Move

9

to the right side

x^{2} - 6 x = x^{2} - x - 15

Subtract

x^{2} - x

from both sides

x^{2} - 6 x - (x^{2} - x) = x^{2} - x - 15 - (x^{2} - x)

Simplify

- 5 x = - 15

Divide both sides by

- 5

x = 3

c, a = b (c + d)

3 (4 n - 1) - 2 = 8 n + 3

y, y = x (y + 2)

y, 3 x + 5 = 9 - 4 y

3 x - 4 = 16

What is the answer to (x-3)^2=(x-3)(x+2) ?
The answer to (x-3)^2=(x-3)(x+2) is x=3
Solve for x: (x-3)^2=(x-3)(x+2)
The solution is x=3