What are the solutions to the equation n^2-9n+20=0 ?

The solutions to the equation n^2-9n+20=0 are n=5,n=4

Find the zeros of n^2-9n+20=0

The zeros of n^2-9n+20=0 are n=5,n=4

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n^{2} - 9 n + 20 = 0

n = 5, n = 4

Solution steps

n^{2} - 9 n + 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

n_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, n_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

n = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

n = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

n = 5, n = 4

\frac{4}{3} \cdot \frac{1}{3}

21 r^{2} - 69 r - 18

x^{2} + x - 90 = 0

\frac{5 y + 2}{x y ^{2}} + \frac{2 x - 4}{4 x y}

What are the solutions to the equation n^2-9n+20=0 ?
The solutions to the equation n^2-9n+20=0 are n=5,n=4
Find the zeros of n^2-9n+20=0
The zeros of n^2-9n+20=0 are n=5,n=4