What is 2/(x-1)> 7/(x+1) ?

The solution to 2/(x-1)> 7/(x+1) is x<-1\lor 1<x< 9/5

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2/(x-1)> 7/(x+1)

\frac{2}{x - 1} > \frac{7}{x + 1}

x < - 1 or 1 < x < \frac{9}{5}

Interval Notation

(- \infty, - 1) \cup (1, \frac{9}{5})

Decimal Notation

x < - 1 or 1 < x < 1.8

Solution steps

\frac{2}{x - 1} > \frac{7}{x + 1}

Rewrite in standard form

\frac{- 5 x + 9}{( x - 1 ) ( x + 1 )} > 0

Identify the intervals

x < - 1 or 1 < x < \frac{9}{5}

\frac{11 !}{( 11 - 5 ) ! 5 !}

3 x^{2} - 14 x - 49

4 (x + 3) \geq 0 or 2 (x + 4) \leq 4

8 - \frac{9 x}{2} < 5

4 x^{2} - 64 m^{2}

What is 2/(x-1)> 7/(x+1) ?
The solution to 2/(x-1)> 7/(x+1) is x<-1\lor 1<x< 9/5