What is the answer to log_{2}(512)=-3x+9 ?

The answer to log_{2}(512)=-3x+9 is x=0

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log_{2}(512)=-3x+9

lo g_{2} (512) = - 3 x + 9

x = 0

Solution steps

lo g_{2} (512) = - 3 x + 9

Switch sides

- 3 x + 9 = lo g_{2} (512)

Move

9

to the right side

- 3 x = 0

Divide both sides by

- 3

x = 0

a, z = a e^{3 t} + b e^{t}

29 w - 18 = 40

3 (4 x - 5) + 2 (11 - 2 x) = 43

\frac{x}{- 6} = 10

\frac{1}{3} (d + 9) = - 12

What is the answer to log_{2}(512)=-3x+9 ?
The answer to log_{2}(512)=-3x+9 is x=0
Solve for x: log_{2}(512)=-3x+9
The solution is x=0