What are the solutions to the equation 0(x)=7x^2+4 ?

The solutions to the equation 0(x)=7x^2+4 are x= 2/(sqrt(7))i,x=-2/(sqrt(7))i

Find the zeros of 0(x)=7x^2+4

The zeros of 0(x)=7x^2+4 are x= 2/(sqrt(7))i,x=-2/(sqrt(7))i

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0 (x) = 7 x^{2} + 4

x = \frac{2}{7} i, x = - \frac{2}{7} i

Solution steps

0 \cdot (x) = 7 x^{2} + 4

Refine

0 = 7 x^{2} + 4

Switch sides

7 x^{2} + 4 = 0

Move

4

to the right side

7 x^{2} = - 4

Divide both sides by

7

x^{2} = - \frac{4}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{7}, x = - - \frac{4}{7}

- \frac{4}{7} = \frac{2}{7} i

- - \frac{4}{7} = - \frac{2}{7} i

x = \frac{2}{7} i, x = - \frac{2}{7} i

\frac{x}{6} = 3

325

\frac{5 !}{4 ! ( 5 - 4 ) !}

(4 x + 20) + (5 x + 16) + (x) = 180

- 2 x - 2 (3 x - 4) = 2 (3 x - 4) + 2 x

What are the solutions to the equation 0(x)=7x^2+4 ?
The solutions to the equation 0(x)=7x^2+4 are x= 2/(sqrt(7))i,x=-2/(sqrt(7))i
Find the zeros of 0(x)=7x^2+4
The zeros of 0(x)=7x^2+4 are x= 2/(sqrt(7))i,x=-2/(sqrt(7))i