What is the answer to 2[3x+1-2(x+4)]-(3x+5)=0 ?

The answer to 2[3x+1-2(x+4)]-(3x+5)=0 is x=-19

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2[3x+1-2(x+4)]-(3x+5)=0

2 [3 x + 1 - 2 (x + 4)] - (3 x + 5) = 0

x = - 19

Solution steps

2 [3 x + 1 - 2 (x + 4)] - (3 x + 5) = 0

Expand

2 (3 x + 1 - 2 (x + 4)) - (3 x + 5) : - x - 19

- x - 19 = 0

Move

19

to the right side

- x = 19

Divide both sides by

- 1

x = - 19

\frac{( x - 4 )}{5} = 8

3 (y + 2) - 10 = 2 (y - 1) + 5

4 a - 8 = a + 13

8 n + 10 = - 24 n + 7

5 x - 4 = - 2 x + 18

What is the answer to 2[3x+1-2(x+4)]-(3x+5)=0 ?
The answer to 2[3x+1-2(x+4)]-(3x+5)=0 is x=-19
Solve for x: 2[3x+1-2(x+4)]-(3x+5)=0
The solution is x=-19