What are the solutions to the equation w^2+30=11w ?

The solutions to the equation w^2+30=11w are w=6,w=5

Find the zeros of w^2+30=11w

The zeros of w^2+30=11w are w=6,w=5

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w^{2} + 30 = 11 w

w = 6, w = 5

Solution steps

w^{2} + 30 = 11 w

Move

11 w

to the left side

w^{2} + 30 - 11 w = 0

Write in the standard form

a x^{2} + b x + c = 0

w^{2} - 11 w + 30 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 30 = 1

w_{1, 2} = \frac{- ( - 11 ) \pm 1}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 11 ) + 1}{2 \cdot 1}, w_{2} = \frac{- ( - 11 ) - 1}{2 \cdot 1}

w = \frac{- ( - 11 ) + 1}{2 \cdot 1} : 6

w = \frac{- ( - 11 ) - 1}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

w = 6, w = 5

(6 + 9 i)^{2}

- 7 x^{2} + 5 x + 12

2 x^{2} = 7 x + 72

(4 x - 2 y) - (2 x - 6 y)

2 x \leq - 6

What are the solutions to the equation w^2+30=11w ?
The solutions to the equation w^2+30=11w are w=6,w=5
Find the zeros of w^2+30=11w
The zeros of w^2+30=11w are w=6,w=5