What are the solutions to the equation 3x(x+1)=-2 ?

The solutions to the equation 3x(x+1)=-2 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6

Find the zeros of 3x(x+1)=-2

The zeros of 3x(x+1)=-2 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6

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3 x (x + 1) = - 2

x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

Solution steps

3 x (x + 1) = - 2

Expand

3 x (x + 1) : 3 x^{2} + 3 x

3 x^{2} + 3 x = - 2

Move

2

to the left side

3 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

3^{2} - 4 \cdot 3 \cdot 2 : 15 i

x_{1, 2} = \frac{- 3 \pm 15 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 15 i}{2 \cdot 3}, x_{2} = \frac{- 3 - 15 i}{2 \cdot 3}

x = \frac{- 3 + 15 i}{2 \cdot 3} : - \frac{1}{2} + i \frac{15}{6}

x = \frac{- 3 - 15 i}{2 \cdot 3} : - \frac{1}{2} - i \frac{15}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

6 - 8 x = 22

3 x^{2} + 36 x + 81

\frac{z ^{- \frac{1}{3}}}{z ^{- \frac{5}{6}}}

2 x^{3} + 11 x^{2} + 20 x + 21

∣ 2 x - 4 ∣ < 6

What are the solutions to the equation 3x(x+1)=-2 ?
The solutions to the equation 3x(x+1)=-2 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6
Find the zeros of 3x(x+1)=-2
The zeros of 3x(x+1)=-2 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6