What is the answer to (0.2)(10)=0.05x+0.4(10-x) ?

The answer to (0.2)(10)=0.05x+0.4(10-x) is x= 40/7

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(0.2)(10)=0.05x+0.4(10-x)

(0.2) (10) = 0.05 x + 0.4 (10 - x)

x = \frac{40}{7}

Decimal Notation

x = 5.71428 \dots

Solution steps

(0.2) (10) = 0.05 x + 0.4 (10 - x)

Switch sides

0.05 x + 0.4 (10 - x) = (0.2) (10)

Remove parentheses:

(a) = a

0.05 x + 0.4 (10 - x) = 0.2 \cdot 10

Multiply the numbers:

0.2 \cdot 10 = 2

0.05 x + 0.4 (10 - x) = 2

Multiply both sides by

100

5 x + 40 (10 - x) = 200

Expand

5 x + 40 (10 - x) : - 35 x + 400

- 35 x + 400 = 200

Move

400

to the right side

- 35 x = - 200

Divide both sides by

- 35

x = \frac{40}{7}

6 w = 90

8 = 3 c + 29

- 10 x + 32 = 2 x + 8

4 p - p = 24

- 2 (- 6 x - 7) = 2 (- 5 x + 7)

What is the answer to (0.2)(10)=0.05x+0.4(10-x) ?
The answer to (0.2)(10)=0.05x+0.4(10-x) is x= 40/7
Solve for x: (0.2)(10)=0.05x+0.4(10-x)
The solution is x= 40/7