What is the answer to solvefor x,f(x+1)=x+1-2 ?

The answer to solvefor x,f(x+1)=x+1-2 is x=(-1-f)/(f-1);\quad f\ne 1

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solvefor x,f(x+1)=x+1-2

solve for

x, f (x + 1) = x + 1 - 2

x = \frac{- 1 - f}{f - 1}; f \neq = 1

Solution steps

f (x + 1) = x + 1 - 2

Add/Subtract the numbers:

1 - 2 = - 1

f (x + 1) = x - 1

Expand

f (x + 1) : x f + f

x f + f = x - 1

Move

f

to the right side

x f = x - 1 - f

Move

x

to the left side

x f - x = - 1 - f

Factor

x f - x : x (f - 1)

x (f - 1) = - 1 - f

Divide both sides by

f - 1; f \neq = 1

x = \frac{- 1 - f}{f - 1}; f \neq = 1

k (x) = - x + 1, k (- 10)

z + (z - 6) - 2 = - 10

x, 5 x + 4 y = 25

x + \frac{x}{3} = \frac{x}{4} + 2

4 (3 x - 5) + 28 = 100

What is the answer to solvefor x,f(x+1)=x+1-2 ?
The answer to solvefor x,f(x+1)=x+1-2 is x=(-1-f)/(f-1);\quad f\ne 1