What are the solutions to the equation 2x^2+8x-18=0 ?

The solutions to the equation 2x^2+8x-18=0 are x=-2+sqrt(13),x=-2-sqrt(13)

Find the zeros of 2x^2+8x-18=0

The zeros of 2x^2+8x-18=0 are x=-2+sqrt(13),x=-2-sqrt(13)

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2 x^{2} + 8 x - 18 = 0

x = - 2 + 13, x = - 2 - 13

Decimal Notation

x = 1.60555 \dots, x = - 5.60555 \dots

Solution steps

2 x^{2} + 8 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 18) = 413

x_{1, 2} = \frac{- 8 \pm 4 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 13}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 13}{2 \cdot 2}

x = \frac{- 8 + 4 13}{2 \cdot 2} : - 2 + 13

x = \frac{- 8 - 4 13}{2 \cdot 2} : - 2 - 13

The solutions to the quadratic equation are:

x = - 2 + 13, x = - 2 - 13

\frac{3}{8} p = 9

(x + 2)^{2} = 28

- 5 < x \leq 4

- 12 r + 4 = 100

x^{4}

What are the solutions to the equation 2x^2+8x-18=0 ?
The solutions to the equation 2x^2+8x-18=0 are x=-2+sqrt(13),x=-2-sqrt(13)
Find the zeros of 2x^2+8x-18=0
The zeros of 2x^2+8x-18=0 are x=-2+sqrt(13),x=-2-sqrt(13)