What are the solutions to the equation -x^2+x-2=0 ?

The solutions to the equation -x^2+x-2=0 are x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2

Find the zeros of -x^2+x-2=0

The zeros of -x^2+x-2=0 are x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2

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- x^{2} + x - 2 = 0

x = \frac{1}{2} - i \frac{7}{2}, x = \frac{1}{2} + i \frac{7}{2}

Solution steps

- x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 2) : 7 i

x_{1, 2} = \frac{- 1 \pm 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 7 i}{2 ( - 1 )}, x_{2} = \frac{- 1 - 7 i}{2 ( - 1 )}

x = \frac{- 1 + 7 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{7}{2}

x = \frac{- 1 - 7 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{7}{2}, x = \frac{1}{2} + i \frac{7}{2}

4 x^{2} - 19 x - 5 = 0

2 x + 5 < 15

\frac{( 3 x + 2 )}{x - 1} > x

x (3 - 4 x) \leq 0

x^{3} + x^{2} - 11 x + 10

What are the solutions to the equation -x^2+x-2=0 ?
The solutions to the equation -x^2+x-2=0 are x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2
Find the zeros of -x^2+x-2=0
The zeros of -x^2+x-2=0 are x= 1/2-i(sqrt(7))/2 ,x= 1/2+i(sqrt(7))/2