What is the answer to solvefor a,v^2=v0^2+2ax ?

The answer to solvefor a,v^2=v0^2+2ax is a=(v^2)/(2x);\quad x\ne 0

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solvefor a,v^2=v0^2+2ax

solve for

a, v^{2} = v 0^{2} + 2 a x

a = \frac{v ^{2}}{2 x}; x \neq = 0

Solution steps

v^{2} = v \cdot 0^{2} + 2 a x

Switch sides

v \cdot 0^{2} + 2 a x = v^{2}

Apply rule

0^{a} = 0

0^{2} = 0

0 \cdot v + 2 a x = v^{2}

Apply rule

0 \cdot a = 0

0 + 2 a x = v^{2}

0 + 2 a x = 2 a x

2 a x = v^{2}

Divide both sides by

2 x; x \neq = 0

a = \frac{v ^{2}}{2 x}; x \neq = 0

2 (2 x + 4) = \frac{3}{4} (24 - 8 x)

- 2 + 9 + 9 w = 9 w + 7

- 5 x - 25 = 65

p, r = \frac{4}{3} (p - q)

t, p = 4 r + 3 t

What is the answer to solvefor a,v^2=v0^2+2ax ?
The answer to solvefor a,v^2=v0^2+2ax is a=(v^2)/(2x);\quad x\ne 0