What are the solutions to the equation t^2= 1/9 ?

The solutions to the equation t^2= 1/9 are t= 1/3 ,t=-1/3

Find the zeros of t^2= 1/9

The zeros of t^2= 1/9 are t= 1/3 ,t=-1/3

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t^{2} = \frac{1}{9}

t = \frac{1}{3}, t = - \frac{1}{3}

Solution steps

t^{2} = \frac{1}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{1}{9}, t = - \frac{1}{9}

\frac{1}{9} = \frac{1}{3}

- \frac{1}{9} = - \frac{1}{3}

t = \frac{1}{3}, t = - \frac{1}{3}

\frac{8 ! 6 !}{5 ! 7 !}

(\frac{1}{2}) ((2)^{7})

8 - (2 a + 7) = a + 40

2 (2 z + 5) = 50

\frac{x + 1}{3} = \frac{x + 2}{5}

What are the solutions to the equation t^2= 1/9 ?
The solutions to the equation t^2= 1/9 are t= 1/3 ,t=-1/3
Find the zeros of t^2= 1/9
The zeros of t^2= 1/9 are t= 1/3 ,t=-1/3