What is the answer to -3(4r-2)+r=-7r-3(-3r-2) ?

The answer to -3(4r-2)+r=-7r-3(-3r-2) is r=0

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-3(4r-2)+r=-7r-3(-3r-2)

- 3 (4 r - 2) + r = - 7 r - 3 (- 3 r - 2)

r = 0

Solution steps

- 3 (4 r - 2) + r = - 7 r - 3 (- 3 r - 2)

Expand

- 3 (- 3 r - 2) : 9 r + 6

- 11 r + 6 = - 7 r + 9 r + 6

Add similar elements:

- 7 r + 9 r = 2 r

- 11 r + 6 = 2 r + 6

Expand

- 3 (4 r - 2) + r : - 11 r + 6

- 11 r + 6 = 2 r + 6

Move

6

to the right side

- 11 r = 2 r

Move

2 r

to the left side

- 13 r = 0

Divide both sides by

- 13

r = 0

x, 5 x + 3 y = - 4

\frac{x - 3}{3} + \frac{2 x - 1}{6} = 4

6 x + 5.76 = 34.14

- 3 y + 4 = 31

g (6) = 6 - 5

What is the answer to -3(4r-2)+r=-7r-3(-3r-2) ?
The answer to -3(4r-2)+r=-7r-3(-3r-2) is r=0
Solve for r: -3(4r-2)+r=-7r-3(-3r-2)
The solution is r=0