What are the solutions to the equation n^2+4=40 ?

The solutions to the equation n^2+4=40 are n=6,n=-6

Find the zeros of n^2+4=40

The zeros of n^2+4=40 are n=6,n=-6

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n^{2} + 4 = 40

n = 6, n = - 6

Solution steps

n^{2} + 4 = 40

Move

4

to the right side

n^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 36, n = - 36

36 = 6

- 36 = - 6

n = 6, n = - 6

5 (2 - y) + y = - 6

y^{3} x - y^{2} x - 2 y^{3} + 2 y^{2}

lo g_{2} (81)

1 2^{2} + 3 5^{2}

\frac{49}{25}

What are the solutions to the equation n^2+4=40 ?
The solutions to the equation n^2+4=40 are n=6,n=-6
Find the zeros of n^2+4=40
The zeros of n^2+4=40 are n=6,n=-6