What is the answer to solvefor a,(B-4D^2)a=h ?

The answer to solvefor a,(B-4D^2)a=h is a= h/(B-4D^2);\quad D\ne (sqrt(B))/2 ,D\ne-(sqrt(B))/2

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solvefor a,(B-4D^2)a=h

solve for

a, (B - 4 D^{2}) a = h

a = \frac{h}{B - 4 D ^{2}}; D \neq = \frac{B}{2}, D \neq = - \frac{B}{2}

Solution steps

(B - 4 D^{2}) a = h

Divide both sides by

B - 4 D^{2}; D \neq = \frac{B}{2}, D \neq = - \frac{B}{2}

a = \frac{h}{B - 4 D ^{2}}; D \neq = \frac{B}{2}, D \neq = - \frac{B}{2}

2 x + 4 = 2 x - 4

g = \frac{A}{4}

\frac{x + 2}{5} = 4

α, 0 α + 0 β - 2 γ = b

x, x + 4 y = - 5

What is the answer to solvefor a,(B-4D^2)a=h ?
The answer to solvefor a,(B-4D^2)a=h is a= h/(B-4D^2);\quad D\ne (sqrt(B))/2 ,D\ne-(sqrt(B))/2