What are the solutions to the equation 24^2+32^2=x^2 ?

The solutions to the equation 24^2+32^2=x^2 are x=40,x=-40

Find the zeros of 24^2+32^2=x^2

The zeros of 24^2+32^2=x^2 are x=40,x=-40

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2 4^{2} + 3 2^{2} = x^{2}

x = 40, x = - 40

Solution steps

2 4^{2} + 3 2^{2} = x^{2}

Switch sides

x^{2} = 2 4^{2} + 3 2^{2}

Simplify

2 4^{2} + 3 2^{2} : 1600

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1600, x = - 1600

1600 = 40

- 1600 = - 40

x = 40, x = - 40

\frac{1}{2} \cdot \frac{1}{2}

\frac{3}{4} \cdot \frac{4}{3}

\frac{( \frac{1}{x + h} - \frac{1}{x} )}{h}

\frac{1}{3 ^{3}}

1 0^{4.4}

What are the solutions to the equation 24^2+32^2=x^2 ?
The solutions to the equation 24^2+32^2=x^2 are x=40,x=-40
Find the zeros of 24^2+32^2=x^2
The zeros of 24^2+32^2=x^2 are x=40,x=-40