What is the answer to 7r+10-3r=9r-5(r-2) ?

The answer to 7r+10-3r=9r-5(r-2) is True for all r

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7r+10-3r=9r-5(r-2)

7 r + 10 - 3 r = 9 r - 5 (r - 2)

True for all r

Solution steps

7 r + 10 - 3 r = 9 r - 5 (r - 2)

Group like terms

7 r - 3 r + 10 = 9 r - 5 (r - 2)

Add similar elements:

7 r - 3 r = 4 r

4 r + 10 = 9 r - 5 (r - 2)

Expand

- 5 (r - 2) : - 5 r + 10

4 r + 10 = 9 r - 5 r + 10

Add similar elements:

9 r - 5 r = 4 r

4 r + 10 = 4 r + 10

Move

10

to the right side

4 r = 4 r

Move

4 r

to the left side

0 = 0

Both sides are equal

True for all r

- 7 + 9 = - 9 + 7

x = 2 - 2 [2 x - 3 (1 - x)]

lo g_{9} (- 3) = 2

x, \frac{2}{5} (x + 1) = g

\frac{x}{20} = \frac{17}{20}

What is the answer to 7r+10-3r=9r-5(r-2) ?
The answer to 7r+10-3r=9r-5(r-2) is True for all r
Solve for r: 7r+10-3r=9r-5(r-2)
The solution is True for all r