What is the answer to a=((b^1+b^2)h)/2 ?

The answer to a=((b^1+b^2)h)/2 is h=(2a)/(b^2+b);\quad b\ne 0,b\ne-1

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a=((b^1+b^2)h)/2

a = \frac{( b ^{1} + b ^{2} ) h}{2}

h = \frac{2 a}{b ^{2} + b}; b \neq = 0, b \neq = - 1

Solution steps

a = \frac{( b ^{1} + b ^{2} ) h}{2}

Switch sides

\frac{( b ^{1} + b ^{2} ) h}{2} = a

Multiply both sides by

2

h (b^{2} + b) = 2 a

Divide both sides by

b^{2} + b; b \neq = 0, b \neq = - 1

h = \frac{2 a}{b ^{2} + b}; b \neq = 0, b \neq = - 1

- \frac{6}{5} x = 12

3 [- x + (2 x + 1)] = x - 1

y, y - 16 = c

y, y - 15 = b

6 x - 5 x = 0

What is the answer to a=((b^1+b^2)h)/2 ?
The answer to a=((b^1+b^2)h)/2 is h=(2a)/(b^2+b);\quad b\ne 0,b\ne-1