What are the solutions to the equation (u+4)^2-48=0 ?

The solutions to the equation (u+4)^2-48=0 are u=4sqrt(3)-4,u=-4sqrt(3)-4

Find the zeros of (u+4)^2-48=0

The zeros of (u+4)^2-48=0 are u=4sqrt(3)-4,u=-4sqrt(3)-4

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(u + 4)^{2} - 48 = 0

u = 43 - 4, u = - 43 - 4

Solution steps

(u + 4)^{2} - 48 = 0

Move

48

to the right side

(u + 4)^{2} = 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

u + 4 = 48 : u = 43 - 4

Solve

u + 4 = - 48 : u = - 43 - 4

The solutions to the quadratic equation are:

u = 43 - 4, u = - 43 - 4

- 3 x^{2} - 2 x - 1 \geq 0

x^{2} = \frac{8}{9} x

- 9 = 9 ∣ m - 1 ∣

15 x^{2} - 14 x + 3

(\frac{1}{2})^{- 4}

What are the solutions to the equation (u+4)^2-48=0 ?
The solutions to the equation (u+4)^2-48=0 are u=4sqrt(3)-4,u=-4sqrt(3)-4
Find the zeros of (u+4)^2-48=0
The zeros of (u+4)^2-48=0 are u=4sqrt(3)-4,u=-4sqrt(3)-4