What are the solutions to the equation 5x^2+18x-8=0 ?

The solutions to the equation 5x^2+18x-8=0 are x= 2/5 ,x=-4

Find the zeros of 5x^2+18x-8=0

The zeros of 5x^2+18x-8=0 are x= 2/5 ,x=-4

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5 x^{2} + 18 x - 8 = 0

x = \frac{2}{5}, x = - 4

Decimal Notation

x = 0.4, x = - 4

Solution steps

5 x^{2} + 18 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

1 8^{2} - 4 \cdot 5 (- 8) = 22

x_{1, 2} = \frac{- 18 \pm 22}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 18 + 22}{2 \cdot 5}, x_{2} = \frac{- 18 - 22}{2 \cdot 5}

x = \frac{- 18 + 22}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 18 - 22}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 4

ln (36) = 6^{2}

ln (x^{2} - y^{2})

2 x^{2} + 3 x = 5

\frac{4}{81}

2 32 a^{3} b^{5} \cdot 8 a^{7} b^{2}

What are the solutions to the equation 5x^2+18x-8=0 ?
The solutions to the equation 5x^2+18x-8=0 are x= 2/5 ,x=-4
Find the zeros of 5x^2+18x-8=0
The zeros of 5x^2+18x-8=0 are x= 2/5 ,x=-4