What is the answer to 3x=(6(2+3^2)-15)/5 ?

The answer to 3x=(6(2+3^2)-15)/5 is x=(-3+3^2*6)/(15)

Solve for x: 3x=(6(2+3^2)-15)/5

The solution is x=(-3+3^2*6)/(15)

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3 x = \frac{6 ( 2 + 3 ^{2} ) - 15}{5}

x = \frac{- 3 + 3 ^{2} \cdot 6}{15}

Decimal Notation

x = 3.4

Solution steps

3 x = \frac{6 ( 2 + 3 ^{2} ) - 15}{5}

Expand

6 (2 + 3^{2}) : 12 + 3^{2} \cdot 6

3 x = \frac{12 + 3 ^{2} \cdot 6 - 15}{5}

Subtract the numbers:

12 - 15 = - 3

3 x = \frac{- 3 + 3 ^{2} \cdot 6}{5}

Divide both sides by

3

x = \frac{- 3 + 3 ^{2} \cdot 6}{15}

4 x - 3 + 2 x + 21 = 60

v, u = v w + z

p + 1.3 = 9.78

14 x - 9 = 10 x + 310 x + 3

x + \frac{2}{3} = \frac{13}{9}

What is the answer to 3x=(6(2+3^2)-15)/5 ?
The answer to 3x=(6(2+3^2)-15)/5 is x=(-3+3^2*6)/(15)
Solve for x: 3x=(6(2+3^2)-15)/5
The solution is x=(-3+3^2*6)/(15)