What is (m^2-6m+8)/(2m-2)*(10)/(m-4) ?

The solution to (m^2-6m+8)/(2m-2)*(10)/(m-4) is (5(m-2))/(m-1)

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simplify (m^2-6m+8)/(2m-2)*(10)/(m-4)

simplify

\frac{m ^{2} - 6 m + 8}{2 m - 2} \cdot \frac{10}{m - 4}

\frac{5 ( m - 2 )}{m - 1}

Solution steps

\frac{m ^{2} - 6 m + 8}{2 m - 2} \cdot \frac{10}{m - 4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( m ^{2} - 6 m + 8 ) \cdot 10}{( 2 m - 2 ) ( m - 4 )}

Factor

m^{2} - 6 m + 8 : (m - 2) (m - 4)

= \frac{( m - 2 ) ( m - 4 ) \cdot 10}{( 2 m - 2 ) ( m - 4 )}

Cancel the common factor:

m - 4

= \frac{( m - 2 ) \cdot 10}{2 m - 2}

Factor

2 m - 2 : 2 (m - 1)

= \frac{( m - 2 ) \cdot 10}{2 ( m - 1 )}

Factor the number:

10 = 2 \cdot 5

= \frac{( m - 2 ) \cdot 2 \cdot 5}{2 ( m - 1 )}

Cancel the common factor:

2

= \frac{( m - 2 ) \cdot 5}{m - 1}

= \frac{5 ( m - 2 )}{m - 1}

(x + 3)^{2} (x - 4)^{3} (2 x + 1)^{2} < 0

∣ 8 x - 2 ∣ \geq 2

e^{- \frac{3}{2}}

8 x^{2} - x - 3 = 0

\frac{4}{3} \cdot 3

What is (m^2-6m+8)/(2m-2)*(10)/(m-4) ?
The solution to (m^2-6m+8)/(2m-2)*(10)/(m-4) is (5(m-2))/(m-1)