What are the solutions to the equation 4x^2=-5x-3 ?

The solutions to the equation 4x^2=-5x-3 are x=-5/8+i(sqrt(23))/8 ,x=-5/8-i(sqrt(23))/8

Find the zeros of 4x^2=-5x-3

The zeros of 4x^2=-5x-3 are x=-5/8+i(sqrt(23))/8 ,x=-5/8-i(sqrt(23))/8

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4 x^{2} = - 5 x - 3

x = - \frac{5}{8} + i \frac{23}{8}, x = - \frac{5}{8} - i \frac{23}{8}

Solution steps

4 x^{2} = - 5 x - 3

Move

3

to the left side

4 x^{2} + 3 = - 5 x

Move

5 x

to the left side

4 x^{2} + 3 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

Simplify

5^{2} - 4 \cdot 4 \cdot 3 : 23 i

x_{1, 2} = \frac{- 5 \pm 23 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 23 i}{2 \cdot 4}, x_{2} = \frac{- 5 - 23 i}{2 \cdot 4}

x = \frac{- 5 + 23 i}{2 \cdot 4} : - \frac{5}{8} + i \frac{23}{8}

x = \frac{- 5 - 23 i}{2 \cdot 4} : - \frac{5}{8} - i \frac{23}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} + i \frac{23}{8}, x = - \frac{5}{8} - i \frac{23}{8}

\frac{50}{50 - 5}

s^{2} - s g - 42 g^{2}

(\frac{5}{6})^{1.6}

14 n^{2} - 97 n - 60

x^{2} + 4 x - 32 < 0

What are the solutions to the equation 4x^2=-5x-3 ?
The solutions to the equation 4x^2=-5x-3 are x=-5/8+i(sqrt(23))/8 ,x=-5/8-i(sqrt(23))/8
Find the zeros of 4x^2=-5x-3
The zeros of 4x^2=-5x-3 are x=-5/8+i(sqrt(23))/8 ,x=-5/8-i(sqrt(23))/8